A floor of building is covered with 2760 tiles each tiles is the shape of a parallelogram of altitude 3 cm and based 4.5 CM find the cost of polishing the tiles at the rate of rs 20 per m^2
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Answered by
10
Answer:
Rs. 65.52
Step-by-step explanation:
Base=4.5 , Height=3
Area= Base× Height=4.5×3=13.5
Area of floor= Area of tile× Number of tiles
= 13.5×2760=37260cm^2
1cm^2=10^-4m^2
37260cm^2=3.2760m^2
cost= Total Area×cost per m^2=3.276×20
= 65.52
Answered by
1
Step-by-step explanation:
BASE= 4.5CM
ALTITUDE OR HEIGHT= 3CM
AREA OF PARALLELOGRAM= BASE× HEIGHT
AREA OF 1 TILE= 4.5×3 = 13.5 CM²
AREA OF 2760 TILES= 13.5× 2760 = 37260 cm²
COST OF POLISHING THE TILES= RS 20/m²
= 37260 CM IN METRE = 37260 ÷ 100
=372.60 m²
= 372.60 × 20
= RS 7452.
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