Question

a floor of the room 8m long and 6m wide is to be covered by square tiles.if measure of each side square tile is 0.8m ,find the number of tiles required to cover the floor ​

Answer 1

Answer:

Step-by-step explanation:

Let "n"be the number of tiles.

Area of floor = n * area of 1 square tile

L*B = n * (0.8)^2

8*6 = n * (0.8)^2

8*6/(0.8)^2 = n

75 = n

Hence, 75 tiles are required .

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Answer 2

Answer:75 tiles

Step-by-step explanation:

Length of room=8m

Breadth of room=6m

Area of room=Length*Breadth

=8*6

=48$m^{2}$

Side of square tile=0.8m

Area of square tile=Side*Side

=0.8*0.8

=0.64$m^{2}$

Number of tiles required to cover the floor=Area of floor/Area of square tile

=48/0.64

=75 tiles