Math, asked by shrijeet, 1 year ago

A floor tile has the shape of a right angled triangle whose hypotenuse is 10 CM and one side is 6 CM. how many tiles are required to cover a floor of area 1296 m2

Answers

Answered by ragh1238
4
H=10cm. area of tile=1/2*height *base. area =1/2*6*8=24cm^2
P=6cm
H^2=P^2+Q^2. area of floor=1296
100=36+Q^2. n.o of tiles required is
Q^2=64. =1296/24=54 tiles
Q=8cm

shrijeet: sorry but it is wrong
shrijeet: Ans =540000
Answered by murtazakpetiwalla
0

Answer:-

H=10cm. area of tile=1/2*height *base. area =1/2*6*8=24cm^2

P=6cm

H^2=P^2+Q^2. area of floor=1296

100=36+Q^2. n.o of tiles required is

Q^2=64. =1296/24=54 tiles

Q=8cm

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