Question

a floor which measures 15 m into 8 M is to be laid with tiles measuring 15 m by 25 cm find the number of tiles required for the for carpet is laid on the floor so that the space of one metre exist between its edges and the edges of the floor what fraction of the floor is uncovered​

Answer 1

Answer: 0.35

Step-by-step explanation:

Area of floor = 1500 x 800 = 1200000 cm²

Area of tile = 50 x 25 = 1250 cm²

No. of tiles required = $\frac{1200000}{1250}$ = 960 tiles

Space = 1 m = 100 cm  on both sides it will be 200 cm

Area of carpet = (1500 - 200) x (800 - 200) = 780,000 cm²

Uncovered area = 1 200 000 - 780,000 = 420,000 cm²

Fraction uncovered = $\frac{420000}{1200000}$ = $\frac{7}{20}$ or 0.35

i hope this helps you