Question

A floor which measures 15 mx 8 m is to be laid with tiles measuring 50 cm by 25 cm. Find the number
of tiles required. Further, if a carpet is laid on the floor so that a space of 1 m exists between its edges
and the edges of the floor, what fraction of the floor is uncovered?
11 am one nane has a blank margin 2.5 cm​

Answer 1

Answer:

Area of Floor = 15*8 = 120m

Area of tile = 0.5*0.25 = 0.75m

So, No of tiles = 120/0.75 = 160 tiles

Dimensions of carpet = 15-2, 8-2

Area of carpet = 13*6 = 78m

Fraction of floor uncovered = (120-78)/120 = 42/120 = 7/20

'11 am one nane has a blank margin 2.5 cm' What was this? I don't Know

Answer 2

Answer:

13.33%

Step-by-step explanation:

$\bf{\huge\mathcal{\boxed{\rm{\mathfrak\blue{Hey Mate:}}}}}$

Total floor area = 15 × 8 = 1200,000 cm²

• 1 tile area = 50×25 cm²

• No. of tiles needed = 1200,000/1250
• = 960

Now , Carpet area = 13*8 = 104 m²

120-104 = 16 m²

• Fraction uncovered = (16/120)*100
• = 13.33%