Question

a floor which measures 15 x 8 metre is to be laid with tiles measuring 15 CM x 25 cm find the number of of the tile requirement​

Answer 1

Answer:

Correct option is

A

960;

20

7

We know, 50cm=0.5m and

25cm=0.25m

Tiles along the length of the room=

0.5

15

= 30 tiles

Tiles along the length of the room=

0.25

8

=32 tiles

Total number of tiles required =30×32 =960 tiles

To leave 1m between the carpet and wall on all sides, the carpet needs to be 2m shorter in each dimension.

Therefore,

(15−2)m(8−2)m

=(13×6)m

=78m

2

Therefore, the room area is 15×8 = 120m

2

The carpet area is 78m

2

The fraction of the area uncovered =

120

120−78

=

120

42

=

20

7

Answer 2

Before, finding the answer. Let's find out on how we can find the answer.

• First, we must find the Area of Floor by using the formula of :

$\boxed{ \sf Area \: of \: Floor = l \times b}$

• Then, we must find the area of tile by using the Same formula.
• Now, we have to convert it to either cm or m. Here, it is converted to m.
• At last, we must divide the Area of Floor with Area of Tile.

____________________

Given :

• Measure of floor =  15 x 8 m
• Measure of tile = 15 x 25 cm

To find :

• number of of the tile requirement​

Solution :

Area of Floor = l × b

                      = 15 × 8

                      = 120 m²

Area of Tile =  l × b

                   = 15 × 25

                   = 375 cm²

Converting from m to cm. [1 m = 100 cm]

m to cm = 375/100

              = 3.75 m

Number of Tiles = $\sf \dfrac{Area \: of \: Floor}{Area \: of \: Tile}$

                           = $\sf \dfrac{120}{3.75}$

                           = 32

Therefore, 32 tiles are required.