Question

A floor which measures 15m × 8m is to be laid with tites measuring 50 cm × 25 cm. Find the number of tiles required. further, if a carpet is laid on the floor so that a space of 1 m exists between its edges and the edges of the floor, what fraction of the floor is uncovered ?

Answer 1

$\mathfrak{ \huge{\underline{solution !}}}$

Area of floor = L × B = 15 × 8 = 120m²

Area of tiles = L × B = 50 × 25 = 1250 cm²

120 m² = 120 × 10,000

= 1200000 cm²

$\bold{numbers \: of \: tiles \: = \frac{area \: of \: floor}{area \: of \: tiles} }$

$= \frac{1200000}{1250 }$

$= 960 \: tiles$

For uncovered area -

15 × 8 = 120 m²

15 - 2 × 8 - 2 = 13 × 6 = 78 m²

170 - 78 = 42 m²

$= \frac{42}{120} = \frac{21}{160}$

$= \boxed{ \frac{7}{20}}$

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Answer 2

Hey mate.....

here's Ur answer.....

Floor's area
= L × B = 15 × 8 = 120m²

Tile's area
= L × B = 50 × 25 = 1250 cm²

120 m² = 120 × 10,000

= 1200000 cm²

uncovered area -

15 × 8 = 120 m²

15 - 2 × 8 - 2 = 13 × 6 = 78 m²

170 - 78 = 42 m^2

42/120 = 21/60 = 7/20.

Hope it Helps❣❤