Question

. A flooring tile has a shape of a parallelogram whose base is 28cmand the corresponding height is 20cm. How many such tiles are required to cover a floor of area 2800m2.​

Answer 1

Answer:

50000 tiles are required to cover a floor of area 2800m²

Step-by-step explanation:

The area of one parallelogram  shape tile,

The area of parallelogram: Base × Height

We have,

Base of the parallelogram= $28cm$

Height of the parallelogram=$20cm$

Area of the flooring tile= [28 × 20]cm²

Area of the flooring tile= 560cm²

Now,

Tiles are required to cover a floor of area 2800m²

We know that 1m² = 10000cm²

Then, floor of area [2800 × 10000]cm²

Floor of area= 28000000cm².

Tiles are required to cover a floor= $\frac{28000000}{560} =50000$