Question

a flooring tile has a shape of a rectangle whose length is 24 cm and the corresponding breadth is 10cm. how many such tiles are required to cover a floor of area 1080 m²​

Answer 1

Here is your answer .

Area if rectangle tile :-

$= \: l \times b \\ = 24 \: cm \times 10cm \\ = 240 { \: cm}^{2}$

Area to required cover :-

$= 1080 { \: cm}^{2}$

240 cm^2 is cover from 1 tile

to cover 1080 cm^2 how many tiles ?

$= \frac{1080}{240} \\ = \frac{108}{24} \\ = 4.5 \: tiles$

4.5 = 4 + 0.5

We reqire 4 tiles and one half tile.

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mark as brainliest answer.

Answer 2

Total area of room = 1080m²

Base of "one" tile = 24cm

Height of "one" tile = 10cm

Area of "one" tile = Base×height

$\huge\purple{24 \times 10}$

$\huge\purple{240 {cm}^{2} }$

$\huge\purple{0.024 {m}^{2} }$

$\red{no. \: of \: tiles \:  =  \frac{area \: of \: room}{area \: of \: one \: tile} }$

$\huge\orange{ \frac{1080}{0.024} }$

$\pink{so... \: 45000 \:tiles \: are \: needed }$