Question

a flooring tile has a shape of parallelogram whose base is 18 cm and the corresponding height is 6 cm. how many such tiles are required to cover a floor of area 540 m square

Answer 1

area of ||gm = b×h
area of 1 tile = 18×6 = 108cm

Area of Floor = 540 m = 5400 cm
No. of tiles = Area of floor/Area of tile
= 5400/108
= 50 tiles

Answer 2

Answer:

50000 tiles

Step-by-step explanation:

We are given a tile whose shape is parallelogram.

Base of tile = 18 cm

Height of tile = 6 cm

Area of tile = $Base\times Height$    

                  = $18 \times 6$    

                  = $108cm^2$    

1 sq.cm = 0.0001 sq.m.

So, 108 sq.cm. = $108 \times 0.0001=0.0108 m^2$

So, area of tile = $0.0108 m^2$

No. of tiles required to cover area 540 sq.m.:

$\frac{540}{0.0108}$

$50000$

Hence 50000 tiles are required to cover floor of area 540 m square