Question

a flooring tile has a shape of parallelogram whose base is 28 cm and the corresponding height is 20 cm how much such tiles are required to cover a floor of area 2800 sq.m ​

Answer 1

Question:

A flooring tile has a shape of parallelogram whose base is 28 cm and the corresponding height is 20 cm.How much such tiles are required to cover a floor of area 2800 sq.m ?

Solution:

First lets find the area of one tile.

$\boxed{\sf{Area\:of\: Parallelogram=Base \times Height}}$

$\implies Area = 28 \times 20 \\ \implies Area = 560c {m}^{2}$

To find the number of tiles required, we need to divide the area of floor by area of tile.

$Area \: of\: floor=2800{m}^{2}\\Area\:of\:floor=2800 \times 100 \times 100 c{m}^{2}\\ Area\:of \: floor=28000000c{m}^{2}$

$\boxed{\sf{Number\:of\:Tiles=\frac{Area\:of\:floor}{Area\:of\:one\:tile}}}$

$\implies Number\:of\:tiles= \frac{28000000}{560} \\ \implies Number\:of\:tiles=50000$

Therefore 50000 tiles are required to cover the floor of area 2800 sq.m.

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Answer 2

ANSWER:-

Given:

A flooring tile has a shape of parallelogram whose base is 28cm & the corresponding height is 20cm.

To find:

The tiles are required to cover a floor of area 2800m².

Explanation:

Parallelogram: A parallelogram is a four-sided shape in which each side is parallel to the side opposite it.

Here, formula of the area of parallelogram: Base × Height

We have,

• Base of the parallelogram= 28cm
• Height of the parallelogram= 20cm

Area of the flooring tile= [28 × 20]cm²

Area of the flooring tile= 560cm²

Now,

• Tiles are required to cover a floor of area 2800m²

We convert into cm²

Therefore,

We know that 1m² = 10000cm²

Then, floor of area [2800 × 10000]cm²

Floor of area= 28000000cm².

• Tiles are required to cover a floor= $\frac{28000000cm^{2} }{560cm^{2} }$
• Tiles are required to cover a floor= 50000 tiles.