Math, asked by muneshinsha9090, 6 months ago

A flooring tile has a shape of parallelogram whose base is 18 cm and the corresponding
height is 6 cm. How many such tiles are required to cover a floor of area 540 m2?
(If required you can split the tiles in whatever way you want to fill up the corners).​

Answers

Answered by Hirendhopavkar
12

Answer:

Given,

Base of the parallelogram - shaped flooring tile =18cm and its height =6cm

So,

Area of one tile =Base×height=18×6=108cm

2

We have the area of floor =540m

2

Hence, number of tiles = Total area / Area of one tile

=

108

(540×100×100)

[∵1m

2

=(100×100)cm

2

]

=50000

Answered by Anonymous
8

Base of the parallelogram-shaped flooring tile = 18 cm and its height = 6 cm

So,

Area of one tile = Base × Height

= 18 × 6

= 108 cm2

We have the area of floor = 540 m2

Hence, number of tiles = Total area/ Area of one tile

= (540 x 100 x 100)/108 [As, 1 m2 = (100 x 100) cm2]

= 50000

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