A flooring tile has a shape of parallelogram whose base is 18 cm and the corresponding
height is 6 cm. How many such tiles are required to cover a floor of area 540 m2?
(If required you can split the tiles in whatever way you want to fill up the corners).
Answers
Answered by
12
Answer:
Given,
Base of the parallelogram - shaped flooring tile =18cm and its height =6cm
So,
Area of one tile =Base×height=18×6=108cm
2
We have the area of floor =540m
2
Hence, number of tiles = Total area / Area of one tile
=
108
(540×100×100)
[∵1m
2
=(100×100)cm
2
]
=50000
Answered by
8
Base of the parallelogram-shaped flooring tile = 18 cm and its height = 6 cm
So,
Area of one tile = Base × Height
= 18 × 6
= 108 cm2
We have the area of floor = 540 m2
Hence, number of tiles = Total area/ Area of one tile
= (540 x 100 x 100)/108 [As, 1 m2 = (100 x 100) cm2]
= 50000
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