Question

a flooring tile has a shape of parallelogram whose base is 24cm and the corresponding heights are 10cm. how many such tiles are required to cover a floor of area 1080m²​

Answer 1

As we know,
Area of parallelogram= base *height
So
Area=24*10
Area of one tile is 240cm^2

Area to be covered is 1080m^2
(1m=100cm, 1m^2 = 10000cm^2)
So 1080m^2=10800000cm^2
10800000/240= 45000
45000 tiles needed

Answer 2

Answer:

Given :-

Dimensions of tiles which is in the shape of parallelogram

Base = 24cm

Height = 10cm

Area of floor = 1080m²

To find :-

We have to find the number of tiles required to cover the floor

Solution :-

Let the number of tiles be n

\sf\ Tiles\ required= \dfrac{Area \ of\ floor}{Area\ of\ tiles } Tiles required=

Area of tiles

Area of floor

Area of tiles = Area of parallelogram

Area of parallelogram= Base× Height

→ Area of a tiles = 24*10

→ Area of a tiles = 240cm²

We have area of floor in m² convert it into cm²

Now 1m²= 10000cm²

→ 1080m² = 10800000cm²

number of tiles = Area of floor / Area of tiles

\begin{gathered}:\implies\sf\ n= \dfrac{\cancel{1080}\times 10000}{\cancel{240}}\\ \\ \\ \\ :\implies\sf\ n= 4.5\times 10000\\ \\ \\ :\implies\sf\ n= 45000\end{gathered}

:⟹ n=

240

1080

×10000

:⟹ n=4.5×10000

:⟹ n=45000

\therefore\underline{\sf\ Number \ of\ tiles\ required= 45000}∴

Number of tiles required=45000