Question

a flooring tile has the sape of a parallelogram whose base is 24 cm and correspnding height is 10 cm. how many such tiles are requirsd to cover a floor of area 1080m2

Answer 1

base of parallelogram=24 cm
height of parallelogram=10 cm
area of parallelogram=b×h=24×10=240 cm^2
area of floor=1080 m^2=10800000 cm^2
no. of tiles required for flooring=10800000÷240=45000 tiles
answer【45000】

Answer 2

$area \: of \: one \: tile = \frac{24}{100} \times \frac{10}{100} \\ = \frac{240}{10000} \\ so \: number \: of \: tiles = \frac{1080}{240} \times 10000 \\ = 4.5 \times 10000 = 45000$