Question

a flooring tile has the shape of a parallelogram whose base is 25 cm and the corresponding height is 10cm how many such tiles are required to cover a floor of area 100 m

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Answer 1

Answer:

Tiles required are 4000.

Step-by-step explanation:

Gívєn -

Flooring tile is a = Parallelogram

Its Base = 25 cm

Its height = 10 cm

Area to be covered by tiles = 100 m²

Tσ fínd -

Tiles required to cover a floor of area 100 m

Sσlutíσn -

First find the area of the tile.

Area of the Parallelogram =

$\boxed{\sf{Base \times Height}}$

$\sf{\implies} \: 25 \times 10$

$\sf{\implies} \: 250\: {cm}^{2}$

Area of one tile = 250 cm².

$\rule{300}{1.5}$

Divide the area to be covered with area of the tile.

Area to be covered = 100 m².

Convert 100 m² to cm²

$\sf{\implies} \: 100 \: {m}^{2} \: to \: {cm}^{2}$

$\sf{\implies} \: 100 \times 10000$

$\sf{\implies} \: 1000000 \: {cm}^{2}$

$\rule{300}{1.5}$

Tiles Required =

$\sf{\implies} \: \dfrac{1000000}{250}$

$\sf{\implies} \: 4000$

Tiles Required = 4000

$\therefore$ Tiles required are 4000.

Answer 2

Answer:

The required tiles are 4000.

Step-by-step explanation:

The bottom tile is a = Parallelogram

Its head = 25 cm

Its length = 10 cm

Area to be covered with tiles = 100 m²

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