Question

A flooring tile has the shape of a parallelogram whose base is 24 cm and the
corresponding height is 10 cm. How many such tiles are required to cover a floor of
area 1080 m²? (If required you can split the tiles in whatever way you want to fill up
the corners).
​

Answer 1

Area of one tile = base×height = 24×10 = 240cm²

Area to be covered = 1080m² = 1080×100×100 cm²

= 1080×10⁴cm²

Therefore total number of tiles that are needed

$= \frac{1080 \times {10}^{4} }{240} = 4.5 \times {10}^{4} = 45000 \: tiles$

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Answer 2

Total area of room = 1080m²

Base of "one" tile = 24cm

Height of "one" tile = 10cm

Area of "one" tile = Base×height

$\huge\purple{24 \times 10}$

$\huge\purple{240 {cm}^{2} }$

$\huge\purple{0.024 {m}^{2} }$

$\red{no. \: of \: tiles \: = \frac{area \: of \: room}{area \: of \: one \: tile} }$

$\huge\orange{ \frac{1080}{0.024} }$

$\pink{so... \: 45000 \:tiles \: are \: needed }$