Question

a flooring tile has the shape of a parallelogram whose base is 240 cm and corresponding height is 20cm .how many such tiles are required to cover a floor of area 1080m ? (if required you can split the tiles in whatever way you want to fill
up then cover​

Answer 1

Solution:

Given : base= 24 cm

Height= 20 cm

Area of floor= 1080 m²= 1080×100×100cm²

[1m²= 10000cm²]

Area of the Parallelogram = base x height

= 24 x 10 = 240 cm²

Area of 1 tile = 240 cm²

[Tiles are in the shape of a parallelogram]

Number of tiles required= Area of the Floor/Area of the Tiles

= 1080 X100 X100/240 =45000

Number of tiles required to cover a Floor= 45000

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BTS AND EXO

Answer 2

Total area of room = 1080m²

Base of "one" tile = 24cm

Height of "one" tile = 10cm

Area of "one" tile = Base×height

$\huge\purple{24 \times 10}$

$\huge\purple{240 {cm}^{2} }$

$\huge\purple{0.024 {m}^{2} }$

$\red{no. \: of \: tiles \: = \frac{area \: of \: room}{area \: of \: one \: tile} }$

$\huge\orange{ \frac{1080}{0.024} }$

$\pink{so... \: 45000 \:tiles \: are \: needed }$