Question

A flooring tile has the shape of a parallelogram whose base is 24 cm and the
corresponding height is 10 cm. How many such tiles are required to cover a floor of 1
area 1080 m?? (If required you can split the tiles in whatever way you want to fill up
the corners).
nieces of different shapes scattered on the floor.​

Answer 1

★Given:-

• A flooring tile has the shape of a parallelogram.

• Base = 24 cm

• Corresponding height = 10 cm

• Area of floor = 1080m²

★To find:-

• No.of.tiles required to cover a floor.

★Solution:-

Conversion of units:-

→1m²=10000cm²

Given,

→Area = 1080m²

⇒ 1080 × 10000cm²

Given that the tiles are in the shape of a parallelogram.

Therefore using the formula,

✦Area of a parallelogram=base×height

Putting values,

⇒Area = 24 ×10

        = 240cm²

Therefore,

→Area of 1 tile = 240cm²

Number of tiles required= Area of the Floor/Area of the Tiles

⇒ 1080×10000/240

⇒45000

Hence,

No.of.tiles required to cover 1 floor are 45000.

_____________

Answer 2

Answer:

To find,

    Required tiles to cover a floor

Solution:-

     Area of Parallelogram shaped tiles = $h \times b$

                                                                = $24 \times 10$ = 240$cm^{2}$

     Area of floor = 1080$m^{2}$

                           = $1080 \times 10^{4} cm^{2}$

No of tiles used = $\frac{Area of floor}{Area of tiles}$

                          = $\frac{1080 \times 10000}{240}$

                          = 45,000 tiles

So the required tiles is 45,000