Question

A flooring tile has the shape of a parallelogram whose base is 24 cm and the
corresponding height is 10 cm. How many such tiles are required to cover a floor of
area 1080 m²? (If required you can split the tiles in whatever way you want to fill up
the corners).
1​

Answer 1

Answer:

Given,

l=24cm (of a tile)

b=10cm (of a tile )

Area of a tile (in parallelogram shape) =l×bcm

2

=24×10

=240cm

2

Total floor area =1080m

2

10000cm

2

= 1m

2

Required number of tiles to cover the floor area =

240

1080×10000

=45000

Answer 2

Given:

Base of flooring tile = 24 cm = 0.24 m

Corresponding height of a flooring tile= 10 cm = 0.10 m

Now:

Area of flooring tile= Base×Altitude

= 0.24×0.10

= 0.024

Area of flooring tile is 0.024m²

Number of tiles required to cover the floor= Area of floor/Area of one tile = 1080/0.024

= 45000 tiles

Hence 45000 tiles are required to cover the floor.