A flooring tile has the shape of a parallelogram whose base is 24cm and the corresponding height is 10cm. How many such tiles are required to cover a floor of area 1080m^2?
Answers
Step-by-step explanation:
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Grade 8
Mathematics
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Chapters in NCERT Solutions - Mathematics , Class 8
Exercises in Mensuration
Question 4
Q4.A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080m^2m
2
?
Ans 4. Area of floor=1080\ m^21080 m
2
To find,
No.of tiles required to cover the floor
=\frac{area\ of\ floor}{area\ of\ 1\ tile}
area of 1 tile
area of floor
Area of tile in the shape =base\ \times heightbase ×height
base=24 cm height=10 cm
Area=24\times1024×10
=240\ cm^2240 cm
2
No.of tiles=\frac{area\ of\ floor}{area\ of\ each\ tile}
area of each tile
area of floor
=\frac{1080\ m^2}{240\ m^2}=
240 m
2
1080 m
2
==1080\times100000\div240\ cm^2=1080×100000÷240 cm
2
=45,000 tiles.