Question

A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2? [If required you can split the tiles in whatever way you want to fill up the corners]​

Answer 1

The answer is 45000 tiles.

STEP BY STEP EXPLANATION :

Area of floor=1080m²

To find,

No.of tiles required to cover the floor

Area of floor / Area of 1 tile

Area of tile in the shape =base ×height

base=24 cm height=10 cm

Area=24cm ×10cm

=240 cm²

No of tiles = Area of floor/ Area of each tile = 1080m²/240m²

= 1080 × 100000/240

= 45000 tiles

Answer 2

Given:

Base of flooring tile = 24 cm = 0.24 m

Corresponding height of a flooring tile= 10 cm = 0.10 m

Now:

Area of flooring tile= Base×Altitude

= 0.24×0.10

= 0.024

Area of flooring tile is 0.024m²

Number of tiles required to cover the floor= Area of floor/Area of one tile = 1080/0.024

= 45000 tiles

Hence 45000 tiles are required to cover the floor.