A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 mº? (If required you can split the tiles in whatever way you want to fill up the corners).
Answers
Step-by-step explanation:
Ans 4. Area of floor=1080\ m^2
To find,
No.of tiles required to cover the floor
=\frac{area\ of\ floor}{area\ of\ 1\ tile}
Area of tile in the shape =base\ \times height
base=24 cm height=10 cm
Area=24\times10
=240\ cm^2
No.of tiles=\frac{area\ of\ floor}{area\ of\ each\ tile}
=\frac{1080\ m^2}{240\ m^2}
==1080\times100000\div240\ cm^2
=45,000 tiles.
Answer:
45,000 tiles.
Step-by-step explanation:
Given,
Given, l=24cm (of a tile)
Given, l=24cm (of a tile) b=10cm (of a tile )
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m 2
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m 2
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m 2 Required number of tiles to cover the floor area =
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m 2 Required number of tiles to cover the floor area = 240
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m 2 Required number of tiles to cover the floor area = 2401080×10000
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m 2 Required number of tiles to cover the floor area = 2401080×10000
Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m 2 Required number of tiles to cover the floor area = 2401080×10000