Math, asked by singplant90, 1 month ago

A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 mº? (If required you can split the tiles in whatever way you want to fill up the corners).​

Answers

Answered by XxkaurxX
0

Step-by-step explanation:

Ans 4. Area of floor=1080\ m^2

To find,

No.of tiles required to cover the floor

=\frac{area\ of\ floor}{area\ of\ 1\ tile}

Area of tile in the shape =base\ \times height

base=24 cm height=10 cm

Area=24\times10

=240\ cm^2

No.of tiles=\frac{area\ of\ floor}{area\ of\ each\ tile}

=\frac{1080\ m^2}{240\ m^2}

==1080\times100000\div240\ cm^2

=45,000 tiles.

Answered by dasmirasree6
1

Answer:

45,000 tiles.

Step-by-step explanation:

Given,

Given, l=24cm (of a tile)

Given, l=24cm (of a tile) b=10cm (of a tile )

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m 2

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m 2

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m 2 Required number of tiles to cover the floor area =

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m 2 Required number of tiles to cover the floor area = 240

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m 2 Required number of tiles to cover the floor area = 2401080×10000

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m 2 Required number of tiles to cover the floor area = 2401080×10000

Given, l=24cm (of a tile) b=10cm (of a tile )Area of a tile (in parallelogram shape) =l×bcm 2 =24×10 =240cm 2 Total floor area =1080m 2 10000cm 2 = 1m 2 Required number of tiles to cover the floor area = 2401080×10000

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