Question

A flooring tile has the shape of a parallelogram whose sides are 28 cm and 10 cm.
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Answer 1

SOLUTION

COMPLETE QUESTION

A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 sq. metre.

EVALUATION

Here it is given that a flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm

So the area of each flooring tile is

$= \sf{24 \times 10 \: \: \: {cm}^{2} }$

$= \sf{240 \: \: \: {cm}^{2} }$

Now the area of the floor = 1080 sq.metre

1 metre = 100 cm

$\therefore \sf{1 \: sq \: metre \: = 10000 \: {cm}^{2} }$

$\therefore \sf{1080 \: sq \: metre \: = 10800000 \: {cm}^{2} }$

Hence the required number of tiles

$\displaystyle\sf{ = \frac{10800000}{240} }$

= 45000

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Answer 2

$\huge\underline{\bf \orange{AnSweR :}}$

• Here it is given that a flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm.

So the area of each flooring tile will be like this :-

→ 24×10cm²

→ 240cm²

Now the area of the floor = 1080 sq.metre

1 metre = 100 cm

∴ 1sq metre= 10000cm²

∴ 1080sq metre= 10800000cm²

Hence the required number of tiles :-

→ 10800000/240

→ 45000 Ans.