Question

A flooring tile has the shape of a parallelogram whose whose base is 24 cm and the corresponding height is 10 cm how many such tiles are required to cover a floor of area 1080 m square (if required you can split the tiles in whatever way you want to fill up the corners​

Answer 1

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Area of parallelogram = Base × Height

Hence, area of 1 tile = $24cm × 10cm = 240cm²$

Required the no. of tiles = $\frac {Area \:of \:floor}{Area \:of \:each \:tile}$

$\frac {1080m²}{240m²}$ = $\frac {(1080×10000)cm²}{240cm²}$

(Since, $1m=100cm$) = $45000$ tiles.

Thus, $45000$ tiles are required to cover a floor of area $1080m².$

Answer 2

Answer:

Given,

Tile is in shape of parallelogram

Base = 24 cm

Base = 24 cmHeight = 10 cm

Now,

Now,Number of tiles required = Area of floor

area of one tile

one tileGiven,

one tileGiven,Area of floor = 1080 m²

= 1080 x (100)² cm²

= 1080 x 100 x 100 cm²

= 1080 x 10000cm²

Now, finding area of tile

Now, finding area of tileArea of tile = Area of parallelogram

Now, finding area of tileArea of tile = Area of parallelogram= Base x Height

Now, finding area of tileArea of tile = Area of parallelogram= Base x Height= 24 x 10

Now, finding area of tileArea of tile = Area of parallelogram= Base x Height= 24 x 10= 240 cm²

Now,

Now,Number of tiles required = Area of floor

Area of one tile

= 1080 x 10000

240

= 1080 x 1000

24

= 540 x 1000

12

= 90 x 1000

2

= 45 x 1000

45 x 1000= 45000

45000* 45000 tiles are required to cover the floor.