Question

A flooring tile has the shape of parallelogram who's base is 24and corresponding height is 10cm how many tiles are required to cover floor of area 1080m²​

Answer 1

Step-by-step explanation:

base= 24/100 m

height = 10/100m

area of one tile = b×h

= 24/ 100 × 10/ 100= 0.026m²

no. of tiles = area of floor/ area of one tile

= 1080/ 0.026 = 41,538 (approx)

Answer 2

Given

• Tile's shape = parallelogram
• height of the tile = 10cm
• base of the tile =24cm
• area of the floor = 1080 cm²

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To find

No.of required tiles

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Concept Used

~Here that concept of Mensuration is used. We have been given that the base and the height of a tile whose shape is parallelogram. First, we will find the area of the single tile by the formula of area of parallelogram then divide the area of single tile by the area of the floor. That will give the no.of required tiles.

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Formula used

${ \underline{ \boxed{ \sf{Area \: of \: parallelogram= b × H}}}}$

where

• b denotes Base
• h denotes height

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Solution

$\sf{ :\implies Area \: of \: tile \: (parallelogram) = 24 × 10} \\ \\ \sf {:\implies Area\:of\: tile \: (parallelogram) = \color{skyblue}240cm²}$

Before we proceed further, first convert the unit metre into centimetre .

♦ 1 metre = 100cm

♦ 1 metre² = 10000 cm²

→1080 m² = 1080 × 10000 cm²

Now,

Let us assume that the no.of tiles required are 'n' in number.

Then,

$\mathtt{ \color{blue}No.of \: tiles \: required \: =\frac{Area \: of \: the \: floor}{Area \: of \: the \: tile}}$

$\sf{\implies No.of tilesrequired=\frac{1080×10000}{240}} \\ \\ \sf{\implies No.of tiles\:required=45×1000}\\ \\ \sf{\implies No.of\:tiles\:required= 45000}$

Therefore 45000 tiles are e required to cover the floor.

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