Math, asked by arunabhandari43349, 6 months ago

a flooring tile has the shape of parallelogram whose base is 24 cm and corresponding height is 10 cm how many such tiles are required to cover a floor of area 1080 m²​

Answers

Answered by YESHIKA11062006
22

Step-by-step explanation:

Area of floor = 1080m square

base of one tile = 24 CM = 0.24m

height of one tile = 10 CM = 0.10 m

Area of one tile = base * height

= 0.10*0.24

= 0.024 m square

No. of tiles = 1080 m square / 0.024 m square

= 45,000 tiles

Hope it help !!!!!!

Answered by mehreennaikoo123
9

Total area of room = 1080m²

Base of "one" tile = 24cm

Height of "one" tile = 10cm

Area of "one" tile = Base×height

\huge\purple{24 \times 10}

\huge\purple{240 {cm}^{2} }

\huge\purple{0.024 {m}^{2} }

\red{no. \: of \: tiles \:  =  \frac{area \: of \: room}{area \: of \: one \: tile} }

\huge\orange{ \frac{1080}{0.024} }

\pink{so... \: 45000 \:tiles \: are \: needed }

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