a flooring tile is a parallelogram who base is 12cm and the corresponding height is 5cm how many such tiles are requires to cover a floor of 3600 m²
Answers
Required question:
flooring tile is a parallelogram whose base is 12cm and the corresponding height is 5 cm how many such tiles are required to cover a floor of 3600m²
AnsWer:-
600,000 tiles are required to cover the area of 3600m²
let's find out !!
given :-
- height = 5cm
- base = 12cm
- area of floor is = 3600m²
convert height and base into meter.
so,
- height = 5/100 = 0.05m
- base = 12/100 = 0.12m
using formula:-
area of parallelogram is = base x height
>> 0.05 x 0.12
>> 0.006
hence the area of parallelogram is 0.006m²
now find the number of tiles are required to cover 3600m² floor.
give:-
so,
- area of floor = 3600m²
- area of 1 tiles = 0.006m²
find:-
hence 600,000 tiles required to cover the area of 3600m²
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>> related question:-
A floor tile has the shape of a parallelogram whose base is 24cm and the corresponding height is 10cm. how many such tiles are required to convert a floor of area 1080m²?
AnsWer:
45000 tiles are required to cover the area of 1080m²
let's find out !!
given:
- the base and height of parallelogram is:
- height = 10cm
- base = 24cm
- area of floor is 1080m²
convert height and base into meter !!
- height = 10 = 10/100 = 0.10m
- base = 24 = 24/100 = 0.24m
find area of parallelogram :
using formula:
area = base x height
>> area = 0.10 x 0.24
>> area = 0.024m²
now, find the number of tiles are required to cover 1080m² floor
give : area of floor÷area of 1 tile
so,
>> 1080÷0.024
>> 45000
hence, 45000 tiles are required to cover the area of 1080m².