a flooring tile is in the shape of a parallelogram having base 12 cm and corresponding height is 8 cm. how many such tiles are required to cover a rectangular floor having dimensions 16 m * 9 m
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Answer:
15000 tiles.
Step-by-step explanation:
For tiles,
Base =12 cm.
height = 8cm.
Area of tile = b×h
= 12×8 =96cm2
For floor,
Base= 16×100=1600cm.
Height =9×100=900cm.
Area of tile =b×h
=1600×900=1440000cm2
No of tiles constitute in floor.
=1440000÷96
=15000 tiles .
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