Math, asked by priyasahoo84, 11 months ago

a flooring tile is in the shape of a parallelogram having base 12 cm and corresponding height is 8 cm. how many such tiles are required to cover a rectangular floor having dimensions 16 m * 9 m​

Answers

Answered by 1236969
14

Answer:

15000 tiles.

Step-by-step explanation:

For tiles,

Base =12 cm.

height = 8cm.

Area of tile = b×h

= 12×8 =96cm2

For floor,

Base= 16×100=1600cm.

Height =9×100=900cm.

Area of tile =b×h

=1600×900=1440000cm2

No of tiles constitute in floor.

=1440000÷96

=15000 tiles .

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