Question

a floral design on a floor is made up of 16 tiles which are triangular the sides of the triangle being 9cm 28cm and 35cm. find the cost of polishing the tiles at the rate of 50 paise per cm²

Answer 1

Hello mate =_=

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Solution:

Semi-perimeter of 1 triangular tile 

=s

=(9+28+35)/2=72/2=36 cm

Using Heron's formula, Area of 1 triangular tile 

=√{s(s−9)(s−28)(s−35)}

=√{36(36−9)(36−28)(36−35)}

=√{36×27×8×1}

=88.2 cm^2   (approx.)        

⇒ Area of 16 triangular tiles =16×88.2=1411.2 cm^2.

Polishing of 1 cm^2 of area costs 50 p

Polishing of 1411.2 cm^2 of area would cost =50×1411.2=70560p= Rs 705.60

hope, this will help you.

Thank you______❤

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Answer 2

Answer:

the answer is 705.6

Step-by-step explanation:

first let us take find the area of 1 triangle out of 16 now,

base = 35cm

and other two sides are 28cm and 9cm now,

s = a + b + c / 2 = 35 + 28 + 9 / 2 = 72 / 2 = 36cm

(s-a) = 36 - 35 = 1

(s-b) = 36 - 28 = 8

(s-c) = 36 - 9 = 27

now let us find teh area,

$\sqrt{s(s-a)(s-b)(s-c)}$

$\sqrt{36 * 1 * 8 * 27}$

88.2cm²

Now. let us multiply it by 16 becuse there are 16 tiles

88.2cm² * 16

1411.2cm²

Now let su find out the how many rupees are there in 50 paise

$\frac{1}{2}$ rupees

multiply it by, 1411.2cm²

1411.2cm² * $\frac{1}{2}$ rupees = 705.6cm²

Now that's your final answer and hope you have understood if you have understood so please give a thanks to its question.