Question

A floral design on a floor on a floor is made up of 16 tiles which are triangular, the sides of the triangular being 9cm,28cm and 35cm.Find the of a polishing the tiles at the rate of 50p per cm².​

Answer 1

$\huge\bigstar\underline\mathfrak\orange{Answer:-}$

$\large\sf\green{Given:-}$

$\sf{a\:=\:9cm}$

$\sf{b\:=\:28cm}$

$\sf{c\:=\:35cm}$

$\large\sf\pink{Formula:-}$

$\longrightarrow$$\sf{s}$ = $\sf\frac{a+b+c}{2}$

$\longrightarrow$$\sf{s}$ = $\sf\frac{9+28+35}{2}$

$\longrightarrow$$\sf{s}$ = $\sf\frac{72}{2}$

$\longrightarrow$$\sf{36cm}$

$\large\sf\red{Area\:of\:triangular\:tile\:is}$

$\longrightarrow$$\sf\sqrt{s(s - a)(s - b)(s - c)}$

$\longrightarrow$$\sf\sqrt{36(36 - 9)(36 - 28)(36 - 35)}$

$\longrightarrow$$\sf\sqrt{36 - 27 - 8}$

$\longrightarrow$$\sf\sqrt{36 \times 9 \times 3 \times 4 \times 2}$

$\longrightarrow$$\sf6 \times 3 \times 2 \times \sqrt{3 \times 2}$

$\longrightarrow$$\sf36 { \sqrt{6cm} }^{2}$

$\longrightarrow$$\sf(36 \sqrt{6} \times 2.42) {cm}^{2}$

$\longrightarrow$$\sf{88.2cm}^{2}$

$\sf\green{Therefore,\:the\:total\:area\:of\:the\:tile\:is\:</p><p>=\:16\:×\: 88.2 cm²}$

$\sf{=\:1411.2\:cm²}$

$\sf\red{Hence,\:The\:cost\:of\:polishing\:per\:cm²\:are\:=\:</p><p>50p}$

$\sf\pink{Than,\:Total\:cost\:of\:polishing\:the\:tiles\:=</p><p>\50p×1411.2 cm²}$

$\longrightarrow$$\sf{=\:Rs.705.60}$

$\sf\orange{Therefore,\:It\:cost\:Rs.\:</p><p> 705.60\:while\:polishing\:the\:complete\:</p><p> tiles}$

${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$

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Answer 2

$\huge{\underline{ \mathtt{\red{❥A} \green{n}\mathtt\blue{s} \purple{w} \mathtt \orange{e}\pink{r}}}}\:$

Area of tiles = 16 x area of 1 Δ

$\sf\mapsto{S=}\dfrac{a+b+c}{2}$

$\sf\mapsto{S=}\dfrac{9+28+35}{2}$

$\sf\mapsto{S=}\dfrac{72}{2}$

$\sf\mapsto{S=36}$

$\sf\underline\red{Area~of~triangular~tile→}$

$\longrightarrow \sf\sqrt{s(s - a)(s - b)(s - c)}$

$→ \sf\sqrt{36(36 - 9)(36 - 28)(36 - 35)}$

$\longrightarrow \sf\sqrt{36 \times 9 \times 3 \times 4 \times 2}$

$\longrightarrow \sf6 \times 3 \times 2 \times \sqrt{3 \times 2}$

$\longrightarrow \sf36 { \sqrt{6cm} }^{2}$

$\longrightarrow\sf(36 \sqrt{6} \times 2.42) {cm}^{2}$

$\longrightarrow \sf{88.2cm}^{2}$

$\sf\purple{Therefore,\:the\:total\:area\:of\:the\:tile\:is\: =\:16\:×\: 88.2 cm²}$

$\sf{=\:1411.2\:cm²}$

Hence,Thecostofpolishingpercm²are=50p

$\sf\green{Than,\:Total\:cost\:of\:polishing\:the\:tiles\:= 50p×1411.2 cm²}$

$\longrightarrow \sf{=\:Rs.705.60}$

$\sf\blue{Therefore,\:It\:cost\:Rs.\: 705.60\:while\:polishing\:the\:complete\: tiles}$

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${\huge{\underline{\small{\mathbb{\pink{HOPE\:HELPS\:UH :)}}}}}}$

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