Question

a Floral design on floor are made up of 16 tiles triangular the sides of triangle being 9 cm , 28 cm , 35 cm , find the cost of polishing the the tiles at 50 paisa for per cm²
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Answer 1

Answer:

Rs 705.60

Step-by-step explanation:

Given :

• a = 35 cm
• b = 28 cm
• c = 6 cm

According to the question :

→ s = $\frac{a+b+c}{2}$

→ s = $\frac{35+28+9}{2}$

→ s = $\dfrac{\cancel{72}}{\cancel{2}}$

→ s = 36 cm

To find :

$\leadsto$ Area of Triangle = $\longrightarrow \sqrt{s(s-a)(s-b)(s-c)}$

$\implies \sqrt{36(36-35)(36-28)(36-9)}$

$\implies \sqrt{36\times1\times8\times27}$

$\implies \sqrt{(6\times6)\times(2\times2)\times2\times(3\times3)\times3}$

$\implies 6\times2\times3\sqrt{2\times3}$

$\implies 36\sqrt{6} \:cm^{2}$

$\implies (36\times2.45) cm^{2} \\\implies 88.2 cm^{2}$

Area of 16 tiles = (16 × 88.2) cm²

                          = 1411.2 cm²

Cost of polishing per cm² area = 50 p

Cost of polishing 1411.2 cm² area

                                    = Rs (1411.2 × 0.50)

                                           = Rs 705.60

Therefore, it will cost Rs 705.60 while polishing all the tiles.

Answer 2

Step-by-step explanation:

Area- 16× area of ∆

S = $\frac{a + b + c}{2}$

S = $\frac{9+28+35}{2}$

S = $\frac{72}{2}$

S = 36

• Area = $\sqrt{s(s-a)(s-b)(s-c)}$

Area = $\sqrt{36(36-9)(36-28)(36-35)}$

=$\: \: \: \: \: \: \: \: \: \: \: \sqrt{36 \times 27 \times 8 \times 1}$

= $\: \: \: \: \: \: \: \: \: \: \: 36 \sqrt{6}$ cm²

Area of tiles = 16×36$\sqrt{6}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 1410.20$

Cost of polishing per cm²= 50

Cost of polishing= 1410.90 ×$\frac{1}{2}$

= $\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 705.45$