A floral design on the floor consists of 3000 tiles.Each tile is in the shape of a parallelogram of altitude 3 cm and Base 5 cm , find cost of polishing the design at the rate of 80 paise per dm
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area of parallelogram of one tile =b×h
=5×3
=15cm^2
area of 3000tiles=3000×15=45000
cost of polishing 1tile =80paise
convert into rupees=80/100=4/5
cost of polishing 45000tiles=45000×4/5=36000rupees
=5×3
=15cm^2
area of 3000tiles=3000×15=45000
cost of polishing 1tile =80paise
convert into rupees=80/100=4/5
cost of polishing 45000tiles=45000×4/5=36000rupees
Akash15111:
hii rosy
Answered by
3
Answer:
area of parallelogram of one tile =base×height
=5×3
=15cm^2
area of 3000tiles= 3000×15
=45000
cost of polishing 1tile =80paise
convert into rupees=80/100
=4/5
cost of polishing 45000tiles=45000×4/5
=36000rupees
This is the correct answer
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