Question

a floral design on the floor of building consist of 280 tiles. each tile is in the shape of parallelogram of altitude 3 cm and base 5cm. Find the cost of polishing the design at the rate of 50 paise per cm​

Answer 1

Answer:

Step-by-step explanation:

Area of  parallelogram = base x height

area of 1 tile = 5 x 3 = 15 cm²

Now  Find the area of 280 tiles

1 tile = 15 cm²

280 tiles = 15 x 280 = 4200 cm²

Now Find the cost:

1 cm² = Rs 50

4200 x 50 =  210,000 Rs

Hence the cost of polishing the deign at the rate of 50 Rs per cm^2  is 210,000.

Answer 2

Answer:

• The cost of polishing the design is 2100 rupees.

Step-by-step explanation:

Given:-

Number of tiles = 280 tiles

Height of each tile (h) = 3cm

Base of each tile (b) = 5cm

As Area of the parallelogram = (b × h)

=> (5×3)cm²

=> (15)cm²

Therefore:-

Area of 1 tile = 15 cm²

Area of 280 tiles = 280×15 cm²

Area of 280 tiles = 4200 cm²

According to the question:-

Cost of polishing 1 cm ² = 50 paise

Cost of polishing 4200 cm² = 4200 × 50 paise

Cost of polishing 4200 cm² = 210,000 paise

We can convert the data into rupees as:-

$\sf{1 \: paise = \frac{1}{100} rupees} \\ \\ \sf{210000 \: paise = 210000 \times \frac{1}{100 }} \\ \\ \sf{210000 \: paise = 2100 \:rupees}$

Hence:-

The cost of polishing the design is 2100 rupees.

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