a flour is made up of 400 Rhombus shaped details with diagonals measuring 18 cm and 12 CM as well as 250 trapezium shaped tiles with parallel sides of 10 cm and 12 cm and height of 8 cm find the area of the floor and also the cost of polishing at @ rupees 300 per metre square
Answers
Answered by
7
A floor
a rhombus:-
area of rhombus = 1/2× base×height
or=1/2×product of diagonals.
then;
area= (1/2×18×12)
=144cm^2
then;
area of 400 rohmbus=(400×144)=27600cm^2
then
trapezium:-
area of trapezium = 1/2× (sum of parallel side)×height
=1/2×(10+12)×8
=88cm^2
area of 250 trapezium =(250×88)cm^2
=22000cm^2.
then
total area of floor =(22000+27600)
=49600cm^2
then
cost of polishing of floor =3000×49600
=148800000 rupee
a rhombus:-
area of rhombus = 1/2× base×height
or=1/2×product of diagonals.
then;
area= (1/2×18×12)
=144cm^2
then;
area of 400 rohmbus=(400×144)=27600cm^2
then
trapezium:-
area of trapezium = 1/2× (sum of parallel side)×height
=1/2×(10+12)×8
=88cm^2
area of 250 trapezium =(250×88)cm^2
=22000cm^2.
then
total area of floor =(22000+27600)
=49600cm^2
then
cost of polishing of floor =3000×49600
=148800000 rupee
Answered by
0
Answer:
same as above it's correct
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