A flow of 10⁷ electrons per second in a conducting wire
constitutes a current of
(a) 1.6´10⁻²⁶A (b) 1.6´10²⁶A
(c) 1.6´10⁻¹²A (d) 1.6´10¹²A
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I think the correct answer is C
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Explanation:
One ampere equals a flow of one Coulomb/second or 6.24*10^18 electrons/second, so a flow of 10^7 electrons/second is equal to 10^7/6.24*10^18 amperes = 1.6*10^-12 amperes or 1.6 picoamperes.
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