a flowchart of program to convert numbers into words in c language
Answers
Answer:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
void main()
{
char num[3];
void convert_to_words(char*);
clrscr();
printf(“Enter any number between 1 to 299 : “);
scanf(“%s”,&num);
convert_to_words(num);
getch();
}
void convert_to_words(char *num)
{
char *single_digits[] = { “zero”, “one”, “two”, “three”, “four”,
“five”, “six”, “seven”, “eight”, “nine”};
char *two_digits[] = {“”, “ten”, “eleven”, “twelve”, “thirteen”, “fourteen”,
“fifteen”, “sixteen”, “seventeen”, “eighteen”, “nineteen”};
char *tens_multiple[] = {“”, “”, “twenty”, “thirty”, “forty”, “fifty”,
“sixty”, “seventy”, “eighty”, “ninety”};
int len = strlen(num);
printf(“\n%s: “, num);
if (len == 1)
{
printf(“%s\n”, single_digits[*num – ‘0’]);
return;
}
while (*num != ‘\0’)
{
if (len == 3)
{
if (*num -‘0’ != 0)
{
printf(“%s “, single_digits[*num – ‘0’]);
printf(“hundred “);
}
–len;
}
else
{
if (*num == ‘1’)
{
int sum = *num – ‘0’ + *(num + 1)- ‘0’;
printf(“%s\n”, two_digits[sum]);
return;
}
else if (*num == ‘2’ && *(num + 1) == ‘0’)
{
printf(“twenty\n”);
return;
}
else
{
int i = *num – ‘0’;
printf(“%s “, i? tens_multiple[i]: “”);
++num;
if (*num != ‘0’)
printf(“%s “, single_digits[*num – ‘0’]);
}
}
++num;
}
}
Explanation:
OUTPUT
ENTER ANY NUMBER BETWEEN (1-299) 5
FIVE