A flowchart to find the sum of first 100 natural numbers
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The list of first 100 natural numbers is:1,2,3,4, .......100The above list forms an AP.Now, we have , n = 100First term,a = 1common difference, d = 2 − 1 = 1Now, sum of first n terms of AP is, Sn = n2[2a+(n−1)d]⇒S100 = 1002[2+(100−1)1]⇒S100 = 50 [2 + 99] = 50 × 101 = 5050
Answered by
1
Answer:
5050
Step-by-step explanation:
First 100 natural numbers = 1,2,3....100
Since it is in A.P.
So, a = first term = 1
d = common difference = 3-2=2-1=1
Sum of first n terms = n/2(2a+(n-1)d)
where a is the first term
d is the common difference
Sum of first 100 natural numbers = 100/2(2(1)+(100-1)1)
= 100/2(2+99)
= 100/2(101)
= 5050
Hence the sum of first 100 natural numbers is 5050
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