Question

a flower bed which is circular surrounded by a path with 5 M the diameter of the circle is equal to 70m what is the area of the path (
$\pi = 3.4$
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Answer 1

ANSWER:-

Diameter of flowerbed=65 m

Diameter of flowerbed=65 mRadius=65/2

Diameter of flowerbed=65 mRadius=65/2Its area=(22/7)x(65/2)x(65/2)

Diameter of flowerbed=65 mRadius=65/2Its area=(22/7)x(65/2)x(65/2)Diameter of flowerbed+path=65+5+5=75 m

Diameter of flowerbed=65 mRadius=65/2Its area=(22/7)x(65/2)x(65/2)Diameter of flowerbed+path=65+5+5=75 mRadius=75/2

Diameter of flowerbed=65 mRadius=65/2Its area=(22/7)x(65/2)x(65/2)Diameter of flowerbed+path=65+5+5=75 mRadius=75/2Its area=(22/7)x(75/2)x(75/2)

Diameter of flowerbed=65 mRadius=65/2Its area=(22/7)x(65/2)x(65/2)Diameter of flowerbed+path=65+5+5=75 mRadius=75/2Its area=(22/7)x(75/2)x(75/2)Area of path=Total area-Ar of flowerbed

Diameter of flowerbed=65 mRadius=65/2Its area=(22/7)x(65/2)x(65/2)Diameter of flowerbed+path=65+5+5=75 mRadius=75/2Its area=(22/7)x(75/2)x(75/2)Area of path=Total area-Ar of flowerbed={(22/7)x(75/2)x(75/2)}-{(22/7)x(65/2)x(65/2)}

Diameter of flowerbed=65 mRadius=65/2Its area=(22/7)x(65/2)x(65/2)Diameter of flowerbed+path=65+5+5=75 mRadius=75/2Its area=(22/7)x(75/2)x(75/2)Area of path=Total area-Ar of flowerbed={(22/7)x(75/2)x(75/2)}-{(22/7)x(65/2)x(65/2)}=1100 sq m

HOPE IT HELPS YOU.