Question

a flower vase is in form of a frestum of cone.the radii of two circular ends are 7cm and 4.2cm.if its depth is 14cm,how much water it can hold

Answer 1

$\textbf{\huge{Question:}}$

A flower vase is in the form of frustum of a cone. The radii of the two circular ends are 7 cm and 4.2 cm. If it's depth is 14 cm, how much water can it hold?

$\textbf{\huge{Solution:}}$

We are provided with the height, bigger radius and smaller radius of the flower vase. We are asked to find the volume of the cone.

$\textbf{Formula:}$

$\sf\:Volume=\dfrac{1}{3}\pi\:(R^{2}+r^{2}+Rr)h$

$\sf\: \implies \: \dfrac{1}{3}\times \dfrac{22}{7}(7^{2}+4.2^{2}+42\times7) 14$

$\implies \: \sf\dfrac{1}{3} \times \dfrac{22}{7} (49 + 17.64 + 294)14 \\ \\ \sf \implies \: \dfrac{2}{3} \times 22 \times 360.64 \\ \\ \sf \implies \: 5289.38 \: {cm}^{3}$

Answer 2

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