A flowerpot drops from the edge of the roof of a multistoried building. calculate the time taken by the pot go cross a particular distance AB of height 2.9m ,the upper point A being 19.6 m below the roof.
Answers
Answered by
31
The time taken by the drop is 0.14 seconds.
Explanation:
- Final velocity can be calculated by using second equation of motion.
- S = ut + 1/2 gt^2
s = 1/2 gt^2
19.6 = 0.5 x 9.8 x t^2
t^2 = 19.6 / 4.9
t^2 = 2 sec
v = at
v = 9.8 x 2
v = 19.6 m/s
- Time taken for the particular height 2.9 m
2.9 = ut + 0.5 at^2
2.9 = 19.6 t + 4.9 t^2
19.6 t + 4.9 t^2 - 2.9 = 0
t = 0.14 sec
Hence the time taken by the drop is 0.14 seconds.
Also learn more
Water is flowing through a horizontal pipe with speed 2m/s and power required to maintain the flow is 20 W. If speed becomes double, then power required will be?
https://brainly.in/question/9018006
Answered by
9
Answer:
1/7 seconds is the answer
Refer the above solution for explanation..
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