Question

A fluid is flowing through tube . At junction it is divided into two cross section with area A/3 and A as shown in figure . The speed of liquid in narrow cross section is (u) will be​

Answer 1

Answer:

From the equation of continuity we get-

Rate=0.1=3Avp+(23A)vq

or

0.1=310−2×20+32(10−2)vq

or

0.1=310−2(20+2vq)

or

vq=230−20=5m/s