Question

A fluid of kinematic viscosity 0.4 sq. cm/s flows through a 8 cm diameter pipe. The maximum velocity for laminar flow will be:

Answer 1

A fluid of kinematic viscosity 0.4 sq. cm/s flows through a 8 cm diameter pipe. The maximum velocity for laminar flow will be:
The maximum velocity will be 1m/s.

Answer 2

Answer:

The maximum velocity for laminar flow will be: 1ms⁻¹.

Explanation:

It is defined as:

R(E)= Reynolds number

$R_{E} =$VD/ν

The accepted transition Reynolds number for flow in a circular pipe is Red,crit = 2000.

where:

V=  The flow velocity,

D= is a characteristic linear dimension, (travelled length of the fluid; hydraulic diameter etc.)

ρ= Fluid density (kg/m3),

μ= Dynamic viscosity (Pa.s),

ν= kinematic viscosity (m²/s);  ν = μ / ρ.

The accepted transition Reynolds number for flow in a circular pipe is ,$R_{E}$ = 2000.

The maximum velocity for laminar flow V=$R_{E}$*ν/D

                                                                    = $\frac{2000*0.4}{8*10^{-3} } = 1ms^{-1}$.