Question

A fly wheel of m1 0.32kg m^2 makes 10 erevolution per second its kinetic energy of rotation is

Answer 1

Hi,

Here is your answer

Given:

I(Moment of inertia)=0.32kg m²

ω(Angualar velocity)=10revolutions per second=62.8 rad/s

To find:

Kinetic energy(K.E)

Solution:

Kinetic energy of a flywheel is given by the formula

K.E= 1/2×I×ω²

Substituting the given datas in the equation

We get,

K.E=1/2×0.32×(62.8)²

K.E=631.01 J

Notes:

1. Remember to convert all the given datas to the SI units before calculating

2. A flywheel is a heavy disc that has a large moment of inertia and that has applications in many fields.