Physics, asked by jyotikurrey26, 4 months ago

 A fly wheel originally at rest is to reach an angular velocity of 42 rad/s in 7 s . Calculate the angular acceleration .



2 radian per second square

4 radian per second square

6 radian per second square

8 radian per second square

Answers

Answered by Mysterioushine
50

Given :

  • Time taken by the fly wheel to reach an angular velocity of 42 rad/s = 7 sec

To Find :

  • The angular acceleration of the fly wheel

Solution :

Now , by using first equation of motion in circular path ;

 \\  \star \: {\boxed{\red{\sf{ \omega_f =  \omega_i +  \alpha  t}}}} \\  \\

Here ,

  • \sf{\omega_f} is final angular velocity
  • ωᵢ is initial angular velocity
  • α is angular acceleration
  • t is time

We have ,

  • \sf{\omega_f} = 42 rad/s
  • ωᵢ = 0 rad/s {Since we are given that the fly wheel is at rest}
  • t = 7 sec

Substituting the values ;

 \\   : \implies \sf \: 42  \: rad .{s}^{ - 1}  = 0 +  \alpha(7 \: s) \\  \\

 \\  :  \implies \sf \: 42 \: rad. {s}^{ - 1}  =  \alpha(7 \: s) \\  \\

 \\  :  \implies \sf \alpha =  \frac{42 \: rad. {s}^{ - 1} }{7 \: s}  \\  \\

 \\   : \implies{\underline{\boxed{\pink{\mathfrak{ \alpha = 6 \: \:  rad. {s}^{ - 2} }}}}}  \: \bigstar \\  \\

Hence ,

  • The angular acceleration of the flywheel is 6 rad/s²
Answered by DARLO20
46

\Large\bf{\color{indigo}GiVeN,} \\

  • A fly wheel originally at rest, i.e. initial angular velocity is zero.

  • Final angular velocity is 42 rad/s.

\Large\bf{\color{cyan}To\:FiNd,} \\

  • Angular acceleration of the wheel.

\Large\bf{\color{lime}CaLcUlaTiOn,} \\

\bf\red{We\:know\:that} \\

\orange\bigstar\:\:\bf{\color{olive}\omega_f\:=\:\omega_i\:+\:\alpha{t}\:} \\

\bf\pink{Where,} \\

  • \bf{\omega_f\:=\:Final\:angular\:velocity}

  • \bf{\omega_i\:=\:Initial\:angular\:velocity}

  • \bf{\alpha\:=\:angular\:acceleration}

  • t = Time period

:\implies\:\:\bf{42\:=\:0\:+\:\alpha\times{7}\:} \\

:\implies\:\:\bf{\alpha\times{7}\:=\:42} \\

:\implies\:\:\bf{\alpha\:=\:\dfrac{42}{7}\:} \\

:\implies\:\:\bf\blue{\alpha\:=\:6\:rad/sec^2\:} \\

\Large\bold\therefore The angular acceleration of the wheel is \bf\purple{6\:rad/sec^2}.

\green\bigstar\:\:{\boxed{\boxed{\color{coral}{\bf{Correct\:Option\:\longrightarrow\:(3)\:6\:rad/sec^2\:}}}}} \\

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