a fly wheel rotates at 420 rpm slows down at a constant rate of 2rad/s² . what time is required to stop the fly wheel
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ωf = ωi + αt
0 = (420 × 2π/60) + (-2)t
t = (420 × 2π/60) / 2
t = 21.99 seconds
Time required to stop the wheel is 21.99 seconds
0 = (420 × 2π/60) + (-2)t
t = (420 × 2π/60) / 2
t = 21.99 seconds
Time required to stop the wheel is 21.99 seconds
Answered by
2
Explanation:
Therefore, the flywheel will take 22 s to stop
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