Question

A fly wheel rotating at 600 rev/min is brought under uniform deceleration and stopped after 2 min then what is angular deceleration in rad/sec square

Answer 1

nice question..
*****Answer*****

α=ω−ω0t=0−600×2π60rad/s120s=20π120=π6rad/s2α=ω−ω0t=0−600×2π60rad/s120s=20π120=π6rad/s2

Answer 2

Given , omega not ( wo) = 600 rev/min = 600×2pie/60 rad/sec
Also time (t) = 2min = 120 sec
Now
we know
angular deceleration = (w-wo)/t
= {0- (600×2×pie)/60}/120
= (20×3.14)/120
= 0.523 rad/sec2 is right answer