A flywheel at rest is to reach an angular velocity of 36 rad/sec, in 6 sec, with a constant angular acceleration. The total angle turned during this interval is :
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Answered by
97
α = ω/t
= (36 rad/s) / 6 s
= 6 rad/s²
θ = ω² / (2 α)
= (36 rad/s)² / (2 × 6 rad/s²)
= 108 rad
Total angle turned during this interval is 108 rad
= (36 rad/s) / 6 s
= 6 rad/s²
θ = ω² / (2 α)
= (36 rad/s)² / (2 × 6 rad/s²)
= 108 rad
Total angle turned during this interval is 108 rad
Answered by
11
Answer:
Explanation:
Theta = 108 radians
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