Question

A flywheel gains a speed of 540 r.p.m in 6 seconds. its angular acceleration will be

Answer 1

w=2nπ
=2π*540/6*60
=3π is the angular acceleration

Answer 2

Answer:

Angular acceleration will be​ =  9.42 radians / s²

Step-by-step explanation:

A flywheel gains a speed of 540 rpm is 6 sec  

$\text{It's angular acceleration will be}:w_1= w_1 + \alpha\cdot t\\\\w_1 = 0$  

where angular acceleration = α

t = 6 sec

$w_2 = 540\text{ rpm}\\\\\implies w_2 = 540\text{ revolution per minute} \\\\\implies w_2 =\frac{540}{60} = 9\text{ revolutions per sec}\\\\\implies w_2 = 9\times 2\pi\text{ radians per second}\\\\\implies w_2 = 9 \times 2\times 3.14\text{ radians per second}\\\\\implies w_2 = 56.52\text{ radians per second}$

⇒ 56.52 = 0 + α (6)

⇒ a = 9.42 radians / s²

Hence, Angular acceleration will be​ =  9.42 radians / s²