Question

A Flywheel gains a speed of 540 rpm in 6 second. Its angular accelaration is (A) 3π rad /sec² (B) 6πrad/sec² C) 4πrad/sec²(D) 12π rad/sec²
please answer the correct​

Answer 1

Explanation:

A Flywheel gains a speed of 540 rpm in 6 second. Its angular accelaration is (A) 3π rad /sec² (B) 6πrad/sec² C) 4πrad/sec²(D) 12π rad/sec²

please answer the correct

Answer 2

Answer:

Given:

• Speed gained by flywheel = 540 rpm
• Time taken = 6 seconds

To Find:

• Angular acceleration of flywheel.

Formula used:

• $\sf Number (n) \ = \ \dfrac{velocity}{time}$
• $\sf Angular \ acceleration \ = \ \dfrac{angular \ velocity}{time}$
• $\omega = 2 \pi n$

Solution:

To find the angular acceleration, first we need to find number (n).

$\implies \sf n \ = \ \dfrac{velocity}{time}$

$\implies \sf n \ = \ \dfrac{540}{60}$

$\implies \sf n \ = \ 9 \ rps$

Now,

$\implies \omega = 2 \pi n = 18 \pi rad/sec$

$\sf Angular \ acceleration = \dfrac{angular \ velocity}{time}$

$\sf Angular \ acceleration = \dfrac{18 \pi}{6}$

$\therefore \sf Angular \ acceleration = 3 \pi rad/sec$