Question

A flywheel gains a speed of 540 rpm is 6 sec
. It's angular acceleration will be​

Answer 1

A flywheel gains a speed of 540 rpm is 6 sec  

. It's angular acceleration will be​

w2 = w1 + αt

w1 = 0  

α = ?

t = 6 sec

w2 = 540 rpm

w2 = 540 revolution per minute

= 540 / 60 = 9 revolutions per sec

= 9  * 2 Pie    radians/s

= 9 * 2 * 3.14 radians/s

= 56.52  radians/s

56.52 = 0 + α (6)

=> a = 9.42 radians / s²

angular acceleration will be​ =  9.42 radians / s²

Answer 2

initial angular velocity, $\omega_0$ = 0

final angular velocity, $\omega$ = 540 rpm = 540 × 2π/60 = 18π rad/s

[ we know, 1 rpm = 2π/60 rad/sec ]

time taken , t = 6 sec

use formula, $\omega=\omega_0+\alpha t$

$18\pi=0+\alpha\times 6$

$3\pi=\alpha$

hence, angular acceleration = 3π or 9.42 rad/s²